Comments on: Please Help!! A phonograph turntable reaches its rated speed of 33 rpm after making 1.1 revolutions. What was ? http://antiquerecordplayers.info/please-help-a-phonograph-turntable-reaches-its-rated-speed-of-33-rpm-after-making-11-revolutions-what-was.htm Wed, 23 May 2012 21:00:32 +0000 http://wordpress.org/?v=2.7.1 hourly 1 By: Greg http://antiquerecordplayers.info/please-help-a-phonograph-turntable-reaches-its-rated-speed-of-33-rpm-after-making-11-revolutions-what-was.htm/comment-page-1#comment-361 Greg Sat, 20 Jun 2009 00:02:56 +0000 http://antiquerecordplayers.info/please-help-a-phonograph-turntable-reaches-its-rated-speed-of-33-rpm-after-making-11-revolutions-what-was.htm#comment-361 w = (6.28 rad)(1.1 rev) / (33 rpm) = .2093 rad/min Ar (Radial Acceleration) = w²r The acceleration cannot be solved without a given radius! You forgot to give the radius, so to find the acceleration, just square (.2093 rad/min) and multiply it by the radius. If you tell me the radius I will do it for you. : ) w = (6.28 rad)(1.1 rev) / (33 rpm) = .2093 rad/min

Ar (Radial Acceleration) = w²r

The acceleration cannot be solved without a given radius! You forgot to give the radius, so to find the acceleration, just square (.2093 rad/min) and multiply it by the radius. If you tell me the radius I will do it for you.

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